Dns question

Ralph W. Reid rreid at sunset.net
Tue May 24 19:33:53 EDT 2005


I just tried `host` and `dig` to look up www.hospital.com and
www.patient.com, and I could not find any IP numbers for either URL.
I'm not sure what you mean by these URL's being 'owned', but they do
not hseem to have any associated IP numbers, hence the DNS look up
failure.  HTH, and have a _great_ day!

On Mon, May 23, 2005 at 10:47:17PM -0400, Sina Bahram wrote:
> Hi all,
> 
> I hope everyone is doing well.
> 
> I appologise for the off topic message, but I know that a great deal of you
> are enthusiasts in networking, and are quite more well versed than myself in
> DNS, which is where my question arises.
> 
> I am building a utility that checks to see if a particular domain is
> registered or not.
> 
> Think of it like a stripped down personalize version of whois, if you will.
> 
> My problem is that I have yet to figure out the absolute minimum
> requirement, in terms of something that can be programmatically determined,
> that says: hey this .com is taken.
> 
> I am using the net::dns module from CPAN in my perl script, and I have tried
> looking at the SOA record, because that is what I have picked up from my
> documentation and google runs as being the absolute requirement.
> 
> Yet, I still get websites like
> 
> www.hospital.com
> 
> And
> 
> www.patient.com
> 
> Which do not return SOA records to my program, yet they are owned ... I
> think both of those, since 1997.
> 
> So, my question is, what is the absolute minimum? I would even appreciate
> documentation pointers, but I just can not learn DNS in and out right now,
> due to other job, research, and student requirements; however, I'm more than
> willing to RTFM, as it were, I just haven't found anything that doesn't
> point me to either MX or SOA records.
> 
> Thanks so much for any assistance.
> 
> Take care,
> Sina

-- 
Ralph.  N6BNO.  Wisdom comes from central processing, not from I/O.
rreid at sunset.net  http://personalweb.sunset.net/~rreid
...passing through The City of Internet at the speed of light!
1 = x^0




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