Scripting Question:

[Dawes, Stephen]

Kirk,

When I tried your solution, I get echo'ed what has been passed to the
script. However, I don't know how arguments were passed to the script at
this point.
trythis 1 2 3 4 5
returns:
1 2 3 4 5

This is what I passed to the script, but it doesn't tell me that I
passed 5 parameters to the script.

Is there a simple way to get this information, or am I going to have to
parse the string $* to determine how many words are on it. 

Kirk, a second question stemming from your response:
KR: It is very simple you just $* instead of $0.  If you enclose it in
quotes you will also get arguments which are meant to be together.
Does this mean that if I put something like 
-l logfilename
that these 2 words would bee seen as one parameter?

Do you have a script example that I could look at?

Steve Dawes
Phone: (403) 268-5527
Email: SDawes at calgary.ca
 
 


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