Bash Problem

[Janina Sajka]

Yeah, David. I typed into the email by hand and did indeed forget the
declaration. But, it was in the actually test.sh file I wrote.

David Bruzos writes:
> Hi Janina:
> Could it be that you are missing the declaration of the "$i" variable.  I added it and it worked for me.  This is what I 
> got:
> 
> #!/bin/bash
> 
> for i in $(ls); do
> 	if [ "$i" != "incoming/" ]; then
> 		echo "$i"
> 	fi
> done
> 
> It seems as if you are missing the "i" after the "for".
> 
> HTH
> 
> David B.
> 
> On Thu, Apr 28, 2005 at 10:03:25AM -0400, Janina Sajka wrote:
> > I'm confused over some simple bash syntax. If I write the following at
> > the bash (ver 3.0) prompt, all works as expected--no errors.
> > 
> > But, if I execute from a script file (which begins with a #!/bin/bash of
> > course), I get:
> > 
> > 	line 4: syntax error near unexpected token `then'
> > 
> > What am I missing? All help much appreciated.
> > 
> > 
> > for in $( ls); do
> > if [ "$i" != "incoming/" ]; then
> > echo $i
> > fi
> > done
> > 
> > 
> > -- 
> > 
> > Janina Sajka				Phone: +1.202.494.7040
> > Partner, Capital Accessibility LLC	http://www.CapitalAccessibility.Com
> > 
> > Chair, Accessibility Workgroup		Free Standards Group (FSG)
> > janina at freestandards.org		http://a11y.org
> > 
> > If Linux can't solve your computing problem, you need a different problem.
> > 
> > 
> > _______________________________________________
> > Speakup mailing list
> > Speakup at braille.uwo.ca
> > http://speech.braille.uwo.ca/mailman/listinfo/speakup
> 
> _______________________________________________
> Speakup mailing list
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-- 

Janina Sajka				Phone: +1.202.494.7040
Partner, Capital Accessibility LLC	http://www.CapitalAccessibility.Com

Chair, Accessibility Workgroup		Free Standards Group (FSG)
janina at freestandards.org		http://a11y.org

If Linux can't solve your computing problem, you need a different problem.