ot, a programming question

Geoff Shang gshang at uq.net.au
Fri Dec 21 20:34:18 EST 2001


The shell expands the wildcard, the wildcard itself never gets passed to
the application.  This can be demonstrated by the following script:

echo $1 $2 $3 $4 $5

Now, you can see here that it's important to read the correct number of
parameters.  Running this script will only output the first 5 matching
files, so you need to be able to read in all the names.  I don't know how
you'd do this in a shell script, but it'd be easy in say C.


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