ot, a programming question

[Geoff Shang]

Hi:

The shell expands the wildcard, the wildcard itself never gets passed to
the application.  This can be demonstrated by the following script:

#!/bin/sh
echo $1 $2 $3 $4 $5

Now, you can see here that it's important to read the correct number of
parameters.  Running this script will only output the first 5 matching
files, so you need to be able to read in all the names.  I don't know how
you'd do this in a shell script, but it'd be easy in say C.

Geoff.